Question #47849

a block of mass 2 kg rests on a rough inclined plane making an angle 30 degree wth horizontal,the coefficient o static friction between the block and the plane is 0.7.the frictional force on block is
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Expert's answer

2014-10-14T09:57:53-0400

Answer on Question #47849, Physics, Mechanics | Kinematics | Dynamics

Question:

A block of mass 2kg2\mathrm{kg} rests on a rough inclined plane making an angle 30 degree with horizontal, the coefficient of static friction between the block and the plane is 0.7.the frictional force on block is

Answer:


Newton's first law of motion:

x:mgsinθ=Ffrx: \quad mg \sin \theta = F_{fr}

Therefore friction force equals


Ffr=mgsinθ=2kg9.8ms2sin30=9.8NF _ {f r} = m g \sin \theta = 2 k g 9. 8 \frac {m}{s ^ {2}} \sin 3 0 {}^ {\circ} = 9. 8 N


Answer: 9.8 N

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