Question #47721

a motorbike together with its rider weighs 150 kg.how much work is needed to set its movement at 15 m/s?
1

Expert's answer

2014-10-13T03:33:00-0400

Answer on Question #47721, Physics, Mechanics - Kinematics - Dynamics

A motorbike together with its rider weighs 150 kg. How much work is needed to set its movement at 15 m/s?

Work to be done is equal to the change in kinetic energy:


W=mv22W = \frac{m v^{2}}{2}


Thus:


W=150kg(15ms)22=16875JW = \frac{150 k g \cdot \left(15 \frac{m}{s}\right)^{2}}{2} = 16875 J


Answer: Work needed: W=16875JW = 16875 J

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