Question #47714

Linear momentum

- By reference to Newton's laws of motion, deduxe that when two particles collide, momentum is conserved
1

Expert's answer

2014-10-10T06:04:14-0400

Answer on Question #47714-Physics-Mechanics-Kinematics-Dynamics

By reference to Newton's laws of motion, deduce that when two particles collide, momentum is conserved.

Answer

From Newton's Third law – when objects are in contact, the forces exerted by the objects on each other are equal and opposite:


FAB=FBA.\overrightarrow{F_{AB}} = - \overrightarrow{F_{BA}}.


From Newton's Second law (collision time is the same) - impulses are equal and opposite:


FABΔt=mAΔvA;FBAΔt=mBΔvB\overrightarrow{F_{AB}}\Delta t = m_A \overrightarrow{\Delta v_A}; \quad \overrightarrow{F_{BA}}\Delta t = m_B \overrightarrow{\Delta v_B}FABΔt=FBAΔtmAΔvA=ΔpA=mBΔvB=ΔpB.\overrightarrow{F_{AB}}\Delta t = - \overrightarrow{F_{BA}}\Delta t \rightarrow m_A \overrightarrow{\Delta v_A} = \overrightarrow{\Delta p_A} = - m_B \overrightarrow{\Delta v_B} = - \overrightarrow{\Delta p_B}.


Therefore changes in momentum are equal and opposite. Total change in momentum is zero:


Δp=ΔpA+ΔpB=ΔpB+ΔpB=0.\overrightarrow{\Delta p} = \overrightarrow{\Delta p_A} + \overrightarrow{\Delta p_B} = - \overrightarrow{\Delta p_B} + \overrightarrow{\Delta p_B} = 0.


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