Question #46896

D=5t to the 2nd. Find the distance d in meters that an object falls in a time t of 5 seconds.

Expert's answer

Answer on Question #46896, Physics, Mechanics | Kinematics | Dynamics

Problem.

D=5t to the 2nd. Find the distance d in meters that an object falls in a time t of 5 seconds.

Solution:

If D(t)=5t2D(t) = 5t^2, then the distance in a time t=5t = 5 seconds equals


D(5)=552=125 m.D(5) = 5 \cdot 5^2 = 125 \text{ m}.


Answer: D(5)=125 mD(5) = 125 \text{ m}.

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