Answer on Question #46806-Physics-Mechanics-Kinematics-Dynamics
Represent the given velocity v = 230 k m h v = 230\frac{km}{h} v = 230 h km in the direction α = 200 \alpha = 200 α = 200 degrees.
Solution
The vector v ⃗ \vec{v} v is shown in the following figure:
We should find coordinates ( v x ; v y ) (v_{x}; v_{y}) ( v x ; v y ) of its end. By definition
v x = v cos α ; v y = v sin α . v _ {x} = v \cos \alpha ; v _ {y} = v \sin \alpha . v x = v cos α ; v y = v sin α .
Substituting values we get
v x = 230 ⋅ cos 200 = − 216.13 k m h ; v _ {x} = 2 3 0 \cdot \cos 2 0 0 = - 2 1 6. 1 3 \frac {k m}{h}; v x = 230 ⋅ cos 200 = − 216.13 h km ; v y = 230 ⋅ sin 200 = − 78.67 k m h . v _ {y} = 2 3 0 \cdot \sin 2 0 0 = - 7 8. 6 7 \frac {k m}{h}. v y = 230 ⋅ sin 200 = − 78.67 h km .
Thus v ‾ = ( − 216.13 k m h ; − 78.67 ) k m h . \overline{\pmb{v}} = \left(-216.13\frac{km}{h}; - 78.67\right)\frac{km}{h}. v v = ( − 216.13 h km ; − 78.67 ) h km .
http://www.AssignmentExpert.com/