Question

A basketball player achieves a hang time of
position (m)
0.505 s in dunking the ball.
What vertical height will he attain? The
acceleration of gravity is 9.8 m/s2 . Answer in units of m

Answer 1

Answer on Question #46407, Physics, Mechanics | Kinematics | Dynamics

A basketball player achieves a hang time of position (m) 0.505 s in dunking the ball. What vertical height will he attain? The acceleration of gravity is $9.8 \, \text{m/s}^2$. Answer in units of m.

Given:

$$\begin{array}{l} t_{all} = 0.505 \, \text{s}, \\ g = 9.8 \, \text{m/s}^2, \\ h = ? \end{array}$$

Solution:

Free fall as the word states is body falling freely due to the gravitational pull of the earth. Consider a body falling freely from height $h$ for time $t$ seconds due to gravity $g$.

Free Fall Formula is

$$h = \frac{1}{2} g t^2$$

The time of falling is

$$t = \frac{t_{all}}{2} = \frac{0.505}{2} = 0.2525 \, \text{s}$$

Thus,

$$h = \frac{1}{2} \cdot 9.8 \cdot 0.2525 = 1.23725 \approx 1.24 \, \text{m}$$

Answer: $h = 1.24 \, \text{m}$

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