Question

Consider the position of a ball thrown down with an initial speed of 21m/s. What will be it's position after 3s? Let the initial position be 0. The acceleration of gravity is 9.8m/s^2. Answer in units of m

Answer 1

Answer on Question #46318, Physics, Mechanics | Kinematics | Dynamics

Consider the position of a ball thrown down with an initial speed of $21\mathrm{m / s}$ . What will be it's position after 3s? Let the initial position be 0. The acceleration of gravity is $9.8\mathrm{m / s}^{\wedge}2$ . Answer in units of m.

Solution.

According to equation of uniformly accelerated motion in projection on the vertical axis:

$$y = y _ {0} + V _ {0} t + \frac {g t ^ {2}}{2}$$

Numerically:

$$L = 0 + 2 1 \frac {m}{s} \cdot 3 s + \frac {9 . 8 \frac {m}{s ^ {2}} \cdot (3 s) ^ {2}}{2} \approx 1 0 7 m$$

Answer: $107\mathrm{m}$

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