Question

A basketball player achieves a hang time of 0.67 s in dunking the ball. What vertical height will he attain? The acceleration of gravity is 9.8m/s^2 answer in units of m

Answer 1

Answer on Question #46317, Physics, Mechanics | Kinematics | Dynamics

Question:

A basketball player achieves a hang time of 0.67 s in dunking the ball. What vertical height will he attain? The acceleration of gravity is $9.8\mathrm{m/s^2}$ answer in units of m

Answer:

Time for motion downward equals:

$$t = \frac{0.67s}{2} = 0.335s$$

Equation of motion equals:

$$h - \frac{gt^2}{2} = 0$$

Therefore:

$$h = \frac{gt^2}{2} = \frac{9.8 \cdot 0.335^2}{2} \, m = 0.55 \, m$$

Answer: 0.55 m

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