Question #45920

Michael is driving his sports car at 30 m/s when he sees a dog on the road ahead. He slams on the brakes and comes to a stop in 2.0 seconds. What was the acceleration of Michael's car?

Expert's answer

Answer on Question #45920, Physics, Mechanics | Kinematics | Dynamics

Question:

Michael is driving his sports car at 30 m/s when he sees a dog on the road ahead. He slams on the brakes and comes to a stop in 2.0 seconds. What was the acceleration of Michael's car?

Answer:

Acceleration by definition equals:


a=ΔvΔta = \frac {\Delta v}{\Delta t}


where Δv\Delta v is change of velocity, Δt\Delta t is time interval.


a=30ms2s=15ms2a = \frac {30 \frac {m}{s}}{2 s} = 15 \frac {m}{s ^ {2}}


Answer: 15ms215\frac{m}{s^2}

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