Question

Please convert 1100 kPa into kg/m*s^2 and kg/km*s^2

also this question:

At 45degree latitude, grativational acceleration as a function of of elevation z above sea level is given by g = a - bz where a = 9.807 m/s^2 and b = 3.32 E -6 s^-2. Determine the height above sea level (z) where the weight of an object will decrease by 0.4%.
z = __________ m

Answer 1

Answer on Question #45448, Physics, Mechanics — Kinematics — Dynamics

Please convert 1100 kPa into $kg/m*s^{2}$ and $kg/km*s^{2}$

also this question:

At 45degree latitude, gravitational acceleration as a function of of elevation z above sea level is given by g = a - bz where a = 9.807 m/$s^{2}$ and b = 3.32 E-6 $s^{-}2$. Determine the height above sea level (z) where the weight of an object will decrease by 0.4%. find z = ? m

Solution

$1100kPa=1100\cdot 10^{3}kg/m*s^{2}=1100\cdot 10^{6}kg/km*s^{2}$

Question.

so we have

$g(z_{1})=a\cdot 0.996$

Hence

$g-a=g(z_{1})-a\cdot 0.996=0.004a=bz_{1}$

$0.004\cdot 9.807=3.32\cdot 10^{-6}z_{1}$

$z_{1}=\frac{0.004\cdot 9.807}{3.32\cdot 10^{-6}}\approx 11815.7\,m$

Answer is z=11815.7 m.