Answer on Question #45039 - Physics - Mechanics | Kinematics | Dynamics
A car is traveling on a level highway at a speed of 15 m / s 15\mathrm{m / s} 15 m/s . A braking force of 3000 N brings the car to a stop in 10 seconds. The mass of the car is?
A) 1500 k g 1500\mathrm{kg} 1500 kg
B) 2000 k g 2000\mathrm{kg} 2000 kg
C) 2500 k g 2500\mathrm{kg} 2500 kg
D) 3000 k g 3000\mathrm{kg} 3000 kg
E) 45,000kg
Solution.
F b F_{b} F b - a braking force;
v 0 v_{0} v 0 - an initial speed of the car;
a a a - a deceleration of the car;
m − a m - a m − a mass of the car;
m g − a mg - a m g − a weight of the car;
t − a t - a t − a time to the stop;
N − a N - a N − a normal force of the car;
From the equation for the velocity:
v ⃗ = v 0 → + a ⃗ t ; \vec {v} = \overrightarrow {v _ {0}} + \vec {a} t; v = v 0 + a t ; v ⃗ = 0 \vec{v} = 0 v = 0 , because car stopped.
0 = v 0 → + a ⃗ t ; 0 = \overrightarrow {v _ {0}} + \vec {a} t; 0 = v 0 + a t ;
Projection on OX:
0 = v 0 x − a x t ; 0 = v _ {0 x} - a _ {x} t; 0 = v 0 x − a x t ; v 0 x = a x t ; v _ {0 x} = a _ {x} t; v 0 x = a x t ; v 0 x = v 0 ; a x = a ; v _ {0 x} = v _ {0}; a _ {x} = a; v 0 x = v 0 ; a x = a ; v 0 = a t ; ( 1 ) v _ {0} = a t; (1) v 0 = a t ; ( 1 )
Newton's second law in vector form:
m a ⃗ = F b → + N ⃗ + m g ⃗ ; m \vec {a} = \overrightarrow {F _ {b}} + \vec {N} + m \vec {g}; m a = F b + N + m g ;
Projection on OX:
− m a x = − F b x + 0 + 0 = − F b x ; - m a _ {x} = - F _ {b x} + 0 + 0 = - F _ {b x}; − m a x = − F b x + 0 + 0 = − F b x ; N = 0 N = 0 N = 0 and m g = 0 mg = 0 m g = 0 - projections on OX are zero.
m a x = F b x ; m a _ {x} = F _ {b x}; m a x = F b x ; a x = F b x m ; a _ {x} = \frac {F _ {b x}}{m}; a x = m F b x ; F b x = F b ; a x = a ; F _ {b x} = F _ {b}; a _ {x} = a; F b x = F b ; a x = a ; a = F b m ; ( 2 ) a = \frac {F _ {b}}{m}; (2) a = m F b ; ( 2 )
From equations (1) and (2) we have:
v 0 = F b m t ; v _ {0} = \frac {F _ {b}}{m} t; v 0 = m F b t ; m = F b v 0 t ; m = \frac {F _ {b}}{v _ {0}} t; m = v 0 F b t ; m = 3000 N 15 m s ⋅ 10 s = 2000 k g . m = \frac {3 0 0 0 N}{1 5 \frac {m}{s}} \cdot 1 0 s = 2 0 0 0 k g. m = 15 s m 3000 N ⋅ 10 s = 2000 k g .
Answer: B) 2000kg.
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