Question #45039

A car is traveling on a level highway at a speed of 15m/s. A braking force of 3000 N brings the car to a stop in 10 seconds. The mass of the car is?
A) 1500kg
B) 2000kg
C) 2500kg
D) 3000kg
E) 45,000kg

Expert's answer

Answer on Question #45039 - Physics - Mechanics | Kinematics | Dynamics

A car is traveling on a level highway at a speed of 15m/s15\mathrm{m / s} . A braking force of 3000 N brings the car to a stop in 10 seconds. The mass of the car is?

A) 1500kg1500\mathrm{kg}

B) 2000kg2000\mathrm{kg}

C) 2500kg2500\mathrm{kg}

D) 3000kg3000\mathrm{kg}

E) 45,000kg

Solution.

FbF_{b} - a braking force;

v0v_{0} - an initial speed of the car;

aa - a deceleration of the car;

mam - a mass of the car;

mgamg - a weight of the car;

tat - a time to the stop;

NaN - a normal force of the car;

From the equation for the velocity:


v=v0+at;\vec {v} = \overrightarrow {v _ {0}} + \vec {a} t;

v=0\vec{v} = 0, because car stopped.


0=v0+at;0 = \overrightarrow {v _ {0}} + \vec {a} t;


Projection on OX:


0=v0xaxt;0 = v _ {0 x} - a _ {x} t;v0x=axt;v _ {0 x} = a _ {x} t;v0x=v0;ax=a;v _ {0 x} = v _ {0}; a _ {x} = a;v0=at;(1)v _ {0} = a t; (1)


Newton's second law in vector form:


ma=Fb+N+mg;m \vec {a} = \overrightarrow {F _ {b}} + \vec {N} + m \vec {g};


Projection on OX:


max=Fbx+0+0=Fbx;- m a _ {x} = - F _ {b x} + 0 + 0 = - F _ {b x};

N=0N = 0 and mg=0mg = 0 - projections on OX are zero.


max=Fbx;m a _ {x} = F _ {b x};ax=Fbxm;a _ {x} = \frac {F _ {b x}}{m};Fbx=Fb;ax=a;F _ {b x} = F _ {b}; a _ {x} = a;a=Fbm;(2)a = \frac {F _ {b}}{m}; (2)


From equations (1) and (2) we have:


v0=Fbmt;v _ {0} = \frac {F _ {b}}{m} t;m=Fbv0t;m = \frac {F _ {b}}{v _ {0}} t;m=3000N15ms10s=2000kg.m = \frac {3 0 0 0 N}{1 5 \frac {m}{s}} \cdot 1 0 s = 2 0 0 0 k g.


Answer: B) 2000kg.

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