Question #44306

The initial velocity u of a bullet in penetrating a distance 's' through a target is reduced by u/n.how far will the bullet proceed through the target before coming to rest?

Expert's answer

Answer on Question #44306 – Physics - Mechanics | Kinematics | Dynamics

The initial velocity uu of a bullet in penetrating a distance 's' through a target is reduced by u/nu/n. how far will the bullet proceed through the target before coming to rest?

Solution:

uu – initial velocity of the bullet;

SS – first traveled distance;

un\frac{u}{n} – final velocity after travelling first distance;

DD – traveled distance before coming to rest;

aa – deceleration of the bullet;

t1t_1 – time of travelling distance SS;

t2t_2 – time of travelling distance DD;

Equation of motion of the bullet for the travelled distance SS:


S=ut1at122S = u t_1 - \frac{a t_1^2}{2}


Rate equation for the bullet:


un=uat1\frac{u}{n} = u - a t_1a=(ut1unt1)=ut1(11n)a = \left(\frac{u}{t_1} - \frac{u}{n t_1}\right) = \frac{u}{t_1} \left(1 - \frac{1}{n}\right)


(2) in(1):


S=ut1ut1(11n)t122S = u t_1 - \frac{u}{t_1} \left(1 - \frac{1}{n}\right) \cdot \frac{t_1^2}{2}S=ut1u2(11n)t1S = u t_1 - \frac{u}{2} \left(1 - \frac{1}{n}\right) t_1t1=Suu2(11n)=Su2+u21n=2Su(n+1)t_1 = \frac{S}{u - \frac{u}{2} \left(1 - \frac{1}{n}\right)} = \frac{S}{\frac{u}{2} + \frac{u}{2} \cdot \frac{1}{n}} = \frac{2S}{u(n + 1)}


(3) in(2):


a=u2Su(n+1)(11n)=u2(n+1)2S(11n)=u2(n+1)2S(n1n)=u2(n+1)2S(n1n)=u2(n21)2nSa = \frac{u}{\frac{2S}{u(n + 1)}} \left(1 - \frac{1}{n}\right) = \frac{u^2(n + 1)}{2S} \left(1 - \frac{1}{n}\right) = \frac{u^2(n + 1)}{2S} \cdot \left(\frac{n - 1}{n}\right) = \frac{u^2(n + 1)}{2S} \cdot \left(\frac{n - 1}{n}\right) = \frac{u^2(n^2 - 1)}{2nS}


Rate equation for the bullet (final velocity of the bullet is zero):


0=uat20 = u - a t_2t2=uat_2 = \frac{u}{a}


Equation of motion of the bullet for the travelled distance DD:


D=ut2at222D = u t_2 - \frac{a t_2^2}{2}


(5) in(6):


D=uuaa(ua)22=u22aD = u \cdot \frac{u}{a} - \frac{a \left(\frac{u}{a}\right)^2}{2} = \frac{u^2}{2a}D=u22u2(n21)2nS=u2nSu2(n21)=nSn21D = \frac {u ^ {2}}{2 \cdot \frac {u ^ {2} (n ^ {2} - 1)}{2 n S}} = \frac {u ^ {2} n S}{u ^ {2} (n ^ {2} - 1)} = \frac {n S}{n ^ {2} - 1}


Answer: Distance that bullet proceed through the target before coming to rest is equal to nSn21\frac{nS}{n^2 - 1}

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