Question #43947

Two partical moving in x directions such that u=3i and v=4i.due to gravition force they are coming downward direction.find their distance when both the velocities are perpendicular to each other.

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Answer on Question #43947 – Physics – Mechanics | Kinematics | Dynamics

Two practical moving in x directions such that u=3i and v=4i due to gravitation force they are coming downward direction. Find their distance when both the velocities are perpendicular to each other.

Solution:

Velocity of the second body considering gravitational force (g – acceleration due to gravity):


u=3i+gtj\vec{u} = 3\vec{i} + g t\vec{j}


Velocity of the second body considering gravitational force


v=4i+gtj\vec{v} = 4\vec{i} + g t\vec{j}


Two vectors are perpendicular, when their scalar product is zero:


uv=3i4i+gtjgtj=12+g2t2>0\vec{u} \cdot \vec{v} = 3\vec{i} \cdot 4\vec{i} + g t\vec{j} \cdot g t\vec{j} = 12 + g^2 t^2 > 0 \Rightarrow


Velocities will not be perpendicular to each other.

**Answer:** both the velocities will not be perpendicular to each other.

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