Question #43570

A particle moves from origin in xy plane with velocuty 3i+6xj find the equation if the path

Expert's answer

Answer on Question #43570 – Physics - Mechanics | Kinematics | Dynamics

A particle moves from origin in xy plane with velocity 3i+6xj3i + 6xj and the equation if the path

Solution


v=3i+6xjv = 3i + 6xj

vv – velocity of the particle;

S – path followed by the particle

Equation if the path:


S(t)=0tv(t)dt=0t(3i+6xj)dt=(3i+6xj)tt0=(3i+6xj)tS(t) = \int_{0}^{t} v(t) \, dt = \int_{0}^{t} (3i + 6xj) \, dt = (3i + 6xj)t \mid \begin{array}{c} t \\ 0 \end{array} = (3i + 6xj)t


Answer: (3i+6xj)t(3i + 6xj)t

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