Answer on Question #43412, Physics, Mechanics — Kinematics — Dynamics
If the gravitational force exerted by the planet Saturn on a 560 kg lunar vehicle is 5.83 * 10 to the power of 3 N, the radius of Saturn is?
Solution
Gravitational force is equal to weight:
F=GMsaturnmvehicleRsaturn2F=\frac{GM_{saturn}m_{vehicle}}{R_{saturn}^{2}}F=Rsaturn2GMsaturnmvehicle
Hence, radius of Saturn is
Rsaturn=GMsaturnmvehicleF=sqrt6.67⋅10−115.68⋅1026⋅5605.83⋅103≈60.2⋅106 m=60200kmR_{saturn}=\sqrt{\frac{GM_{saturn}m_{vehicle}}{F}}=sqrt{\frac{6.67\cdot 10^{-11}5.68\cdot 10^{26}\cdot 560}{5.83\cdot 10^{3}}}\approx 60.2\cdot 10^{6}\,m=60200kmRsaturn=FGMsaturnmvehicle=sqrt5.83⋅1036.67⋅10−115.68⋅1026⋅560≈60.2⋅106m=60200km
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