Question #43411

While in a geosynchronous orbit around Earth, a 560 kg communications satellite has a weight of 125 N. The distance of the satellite from the Earth's surface is?

Expert's answer

Answer on Question #43411, Physics, Mechanics — Kinematics — Dynamics

While in a geosynchronous orbit around Earth, a 560 kg communications satellite has a weight of 125 N. The distance of the satellite from the Earth’s surface is?

Solution

Weight is equal to gravity force.

F=GMEarthmsat(REarth+Rorbit)2F=\frac{GM_{Earth}m_{sat}}{(R_{Earth}+R_{orbit})^{2}}

Hence, distance to surface is

Rorbit=GMEarthmsatFREarth=6.6710115.971024560125N42.21066,4106=R_{orbit}=\sqrt{\frac{GM_{Earth}m_{sat}}{F}}-R_{Earth}=\sqrt{\frac{6.67\cdot 10^{-11}\cdot 5.97\cdot 10^{24}\cdot 560}{125N}}\approx 42.2\cdot 10^{6}-6,4\cdot 10^{6}=

=35.8106m=35800km=35.8\cdot 10^{6}\,m=35800km

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