Question

The static friction force encountered by a titanium piston in a Formula One racing car engine is 3.36 N. If the coefficient of static friction is .15, the magnitude of the applied force necessary to start the piston is?

Answer 1

Answer on Question #43409 – Physics - Mechanics | Kinematics | Dynamics

The static friction force encountered by a titanium piston in a Formula One racing car engine is 3.36 N. If the coefficient of static friction is .15, the magnitude of the applied force necessary to start the piston is?

**Solution:**

$\mathrm{F_{fric}} = 3.36\mathrm{N}$ – friction force encountered by a titanium piston;

$k = 0.15$ – coefficient of static friction;

Newton's second law for the piston (friction force just matching the applied force):

$$\mathrm{F_{applied}} - \mathrm{F_{fric}} = 0$$ $$\mathrm{F_{applied}} = \mathrm{F_{fric}} = 3.36\ \mathrm{N}$$

Answer: magnitude of the applied force is equal to

http://www.AssignmentExpert.com/