Question

If the 7.50 kg block experiences a friction force of 12.8 N, the magnitude of the acceleration of this system is?

Answer 1

Answer on Question #43408, Physics, Mechanics | Kinematics | Dynamics

If the 7.50 kg block experiences a friction force of 12.8 N, the magnitude of the acceleration of this system is?

Solution:

The friction force is the force exerted by a surface as an object moves across it or makes an effort to move across it.

$$F _ {f r i c t} = m a$$

Thus, the acceleration is

$$a = \frac {F _ {f r i c t}}{m} = \frac {1 2 . 8}{7 . 5 0} = 1. 7 1 \mathrm {m / s ^ {2}}$$

Answer: $a = 1.71 \, \text{m/s}^2$ .

http://www.AssignmentExpert.com/