Question

A speedboat accelerates uniformly form rest at 3.0m/s squared. The distance the speedboat will travel between 4.0s and 6.0s is?

Answer 1

Answer on Question #43404, Physics, Mechanics — Kinematics — Dynamics —

A speedboat accelerates uniformly form rest at 3.0m/s squared. The distance the speedboat will travel between 4.0s and 6.0s is?

Solution

Law of motion of boat is

$s=at^{2}/2$

Hence, distance traveled between 4.0s and 6.0s is

$s_{2}-s_{1}=a/2(t_{2}^{2}-t_{1}^{2})=3/2(6^{2}-4^{2})=30\,m$

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