Question

what is the difference in blood pressure between the top of the head and bottom of the feet of 1.6m tall person standing vertically (density of blood p = 1.05 x 10^3 kg/m^3)
A. 1.6 x 10^4 Pa
B. 1.6 x 10^5 Pa
C. 3.2 x 10^5 Pa
D. 1.6 x 10^6 Pa
E. 3.2 x 10^6 Pa

Answer 1

Answer on Question #43270, Physics, Mechanics | Kinematics | Dynamics

What is the difference in blood pressure between the top of the head and bottom of the feet of 1.6m tall person standing vertically (density of blood $\rho = 1.05 \times 10^{3} \, \mathrm{kg/m^{3}}$)

A. $1.6 \times 10^{4} \, \mathrm{Pa}$

B. $1.6 \times 10^{5} \, \mathrm{Pa}$

C. $3.2 \times 10^{5} \, \mathrm{Pa}$

D. $1.6 \times 10^{6} \, \mathrm{Pa}$

E. $3.2 \times 10^{6} \, \mathrm{Pa}$

Solution:

The difference in static pressure is density (rho) times gravity (g) times difference in height (h)

$$\Delta P = \rho g \Delta h$$

Thus,

$$\Delta P = (1.05 \times 10^{3} \, \mathrm{kg/m^{3}}) (9.8 \, \mathrm{m/s^{2}}) (1.6 \, \mathrm{m}) = 1.65 \times 10^{4} \, \mathrm{Pa}$$

Answer: A. $1.6 \times 10^{4} \, \mathrm{Pa}$

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