Question

A car moves 30m north and then 40m east then what is the magnitude of displacement of the car?

Answer 1

Answer on Question #43016 – Physics - Mechanics | Kinematics | Dynamics

A car moves 30m north and then 40m east then what is the magnitude of displacement of the car?

Solution:

$S_{1} = 30\,m$ — distance that car has travelled north;

$S_{2} = 40\,m$ — distance that car has travelled east;

From the righth triangle ABC using the Pythagorean Theorem:

$$D = \sqrt{S_{1}^{2} + S_{2}^{2}} = \sqrt{(30\,m)^{2} + (40\,m)^{2}} = 50\,m$$

Answer: the magnitude of displacement of the car is equal to $50\,m$.

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