Question

For a huge luxury liner to move with constant velocity, its engines need to supply a forward thrust of 7.70x10^5 N. What is the magnitude of the resistive force exerted by the water on the cruise ship?

Answer 1

Answer on Question #42967 – Physics - Mechanics | Kinematics | Dynamics

For a huge luxury liner to move with constant velocity, its engines need to supply a forward thrust of $7.70 \times 10^{5} \mathrm{~N}$. What is the magnitude of the resistive force exerted by the water on the cruise ship?

**Solution:**

Newton's second law ($v = const \Rightarrow a = 0$):

Magnitude of the resistive force exerted by the water on the cruise ship is equal to the magnitude of the forward thrust, but directions of the forces are opposite (according to the Newton's Third Law)

$$F_{res} - F_{thrust} = ma = 0$$

Hence,

$$F_{res} = F_{thrust} = 7.70 \cdot 10^{5} N$$

**Answer:** Magnitude of the resistive force exerted by the water on the cruise ship is equal to $7.70 \cdot 10^{5} N$

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