Question

Vectors A and B have scalar product -6.00 and their vector product has magnitude 9.00.What is the angle between these two vectors?

Answer 1

Magnitudeof vector productA=|a| |b| sin( teta) =9Dot productD=|a| |b| cos( teta) =-6A/D=sin( teta)/ cos( teta)=-1.5 => teta=arctan(-1.5)=-56.3 degrees