Question #42639

A stone of mass 0.49 kg is accelerated upward at a rate of 1.5 m/s. What force is applied to make this happen,

Expert's answer

Answer on Question #42639, Physics, Mechanics | Kinematics | Dynamics

Question:

A stone of mass 0.49 kg0.49\ \mathrm{kg} is accelerated upward at a rate of 1.5 m/s1.5\ \mathrm{m/s}. What force is applied to make this happen?

Answer:

Newton’s second law of motion:

The acceleration of a body is directly proportional to, and in the same direction as, the net force acting on the body, and inversely proportional to its mass:


Fnet=maF_{net} = ma


Net force acting on the body equals:


Fnet=FmgF_{net} = F - mg


where mgmg is gravitational force.

Therefore:


Fmg=maF - mg = maF=m(a+g)=0.49(1.5+9.8)kgms2=5.5 NF = m(a + g) = 0.49(1.5 + 9.8)kg \cdot \frac{m}{s^2} = 5.5\ N


Answer: 5.5 N5.5\ N

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