A string of length L and mass M is lying on a horizontal table. A force F is applied at one of its ends. Tension in the string at a distance x from the end at which force applied is
(a) zero
(b) F
(c) F(L−x)/L
(d) F(L−x)/M
If the string is not fixed and doesn't move because of friction, then the tension in the string at a distance x from the end at which force applied is T=F(L−x)/L,
Answer:(c) F(L−x)/L
If the table is frictionless and the another end of thestring is fixed, then each point of the string has the same tension T = F.
Answer: (b) F.
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