Question #42080

The planet earth is 1.5 10^11 from the sun and orbits the sun in one year. The planet
Pluto takes 248 years to orbit the sun. How far is Pluto from the sun?

Expert's answer

Answer on Question #42080, Physics, Mechanics | Kinematics | Dynamics

The planet earth is 1.5×1011m1.5 \times 10^{11} \, \text{m} from the sun and orbits the sun in one year. The planet Pluto takes 248 years to orbit the sun. How far is Pluto from the sun?

Solution:

Given:


aEarth=21.51011ma _ {E a r t h} = 2 1. 5 \cdot 1 0 ^ {1 1} \mathrm {m}PPluto=248 yearsP _ {P l u t o} = 2 4 8 \text { years}aPluto=?a _ {P l u t o} =?


The third Kepler law captures the relationship between the distance of planets from the Sun, and their orbital periods.

"The square of the orbital period of a planet is directly proportional to the cube of the semimajor axis of its orbit."

Mathematically, the law says that the expression P2/a3P^2 / a^3 has the same value for all the planets in the solar system, where PP is period and aa is distance from the Sun.


PEarth2aEarth3=PPluto2aPluto3\frac {P _ {E a r t h} ^ {2}}{a _ {E a r t h} ^ {3}} = \frac {P _ {P l u t o} ^ {2}}{a _ {P l u t o} ^ {3}}aPluto=aEarth3PPluto2PEarth2a _ {P l u t o} = a _ {E a r t h} ^ {3} \sqrt {\frac {P _ {P l u t o} ^ {2}}{P _ {E a r t h} ^ {2}}}aPluto=1.51011248212=1.5101139.473=59.21011ma _ {P l u t o} = 1. 5 \cdot 1 0 ^ {1 1} \sqrt {\frac {2 4 8 ^ {2}}{1 ^ {2}}} = 1. 5 \cdot 1 0 ^ {1 1} \cdot 3 9. 4 7 3 = 5 9. 2 \cdot 1 0 ^ {1 1} \mathrm {m}


Answer. aPluto=59.21011ma_{Pluto} = 59.2 \cdot 10^{11} \, \text{m}

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