Question

A NUMBER OF TUNING FORKS ARE ARRANGED IN ORDER OF INCREASING FREQUENCY AND ANY 2 SUCCESSIVE TUNING FORKS PRODUCE 4BEATS/S WHEN SOUNDED TOGETHER. IF THE LAST TUNING FORK HAS A FREQUENCY OCTAVE HIGHER THAN THE FIRST AND FREQUENCY OF THE FIRST IS 256 Hz. THEN THE NUMBER OF TUNING FORKS IS :
1. 63
2. 64
3. 65
4. 66

Answer 1

The frequency of the last tuningfork octave higher than the first one of a frequency 226 Hz. So, it equals 512
Hz. Thus, the number of tuning forces is
(512-256)/4 = 64.

Answer is 2. 64 tuning forces.