A NUMBER OF TUNING FORKS ARE ARRANGED IN ORDER OF INCREASING FREQUENCY AND ANY 2 SUCCESSIVE TUNING FORKS PRODUCE 4BEATS/S WHEN SOUNDED TOGETHER. IF THE LAST TUNING FORK HAS A FREQUENCY OCTAVE HIGHER THAN THE FIRST AND FREQUENCY OF THE FIRST IS 256 Hz. THEN THE NUMBER OF TUNING FORKS IS :
1. 63
2. 64
3. 65
4. 66
1
Expert's answer
2014-05-06T13:16:56-0400
The frequency of the last tuningfork octave higher than the first one of a frequency 226 Hz. So, it equals 512 Hz. Thus, the number of tuning forces is (512-256)/4 = 64.
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Sir send the full solution.... that how we get 226 hz.. in your ans.
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