Question

In an experiment, 20 complete osillations were made in 14 .3 seconds. Determine the value of the square of the period, $T^{2}

0511s2

13402

2004s2

4890s2

Answer 1

Answer on Question #41749 – Physics - Mechanics | Kinematics | Dynamics

In an experiment, 20 complete osillations were made in 14 .3 seconds. Determine the value of the square of the period, $T^{2}

0511s2

13402

2004s2

4890s2

Solution:

Formula for the period (N- number of complete osillations):

$$T = \frac {t}{N} \Rightarrow T ^ {2} = \left(\frac {t}{N}\right) ^ {2} = \left(\frac {14.3\ s}{20}\right) ^ {2} = 0.511s^2$$

Answer: square of the period is equal to $0.511s^2$.

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