Question #41351

The equation of motion for a particular mass at the end of a spring is
x=0:40cos(0:70t−30)
m. For this oscillation, find the amplitude and the period.

a. 40 cm; 8.97 s
b. 20 cm ; 4.75s
c. 40 m; 9.87 s
d. 20 m; 4.75 s

Expert's answer

Answer on Question#41351, Physics, Other

Question:

The equation of motion for a particular mass at the end of a spring is

x=0.40cos(0.70t30)mx = 0.40 \cos(0.70t - 30) \, \text{m} . For this oscillation, find the amplitude and the period.

a. 40cm40 \, \text{cm} ; 8.97 s

b. 20cm20 \, \text{cm} ; 4.75 s

c. 40m40 \, \text{m} ; 9.87 s

d. 20m20 \, \text{m} ; 4.75 s

Answer:

The general form of the sine function is:


y=Asin(Bx+C)+Dy = A \sin (B x + C) + D


where:

AA is the amplitude of the function

The period of the function is: T=2πBT = \frac{2\pi}{B}

Therefore, amplitude equals:


A=0.4m=40cmA = 0.4 \, \text{m} = 40 \, \text{cm}


And period equals:


T=2π0.7=8.97sT = \frac{2\pi}{0.7} = 8.97 \, \text{s}


Answer: a. 40cm40 \, \text{cm} ; 8.97 s

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