Answer on Question#41348, Physics, Mechanics
The position of a particle along the x-axis depends on the time according to the equation according to the at²-bt³, where x is in metres and t in seconds. What are the dimensions of and units of a and b?
a. LT⁻², m/s²; LT⁻³, m/s³
b. LT², m/s⁻²; LT³, m/s⁻³
c. L⁻¹T⁻², m⁻¹/s²; LT⁻³, m/s³
d. LT⁻², m/s²; L⁻²T⁻³, m⁻²/s³
Solution:
Given:
In this equation x is a distance. The unit of x is length (L) in meters (m).
So both terms being subtracted, at² and bt³, have the units of length.
Since at² has units of L, since you get L by multiplying a by a time squared (T²), then a must have units of L/T² or m/s² (LT⁻²).
We can do similar reasoning for bt³. We get L out by multiplying b by a time cubed. So b has to have units of L divided by time³.
Thus b dimension is LT⁻³, m/s³.
Answer. a. LT⁻², m/s²; LT⁻³, m/s³.
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