Question #41295

A force of 90 N is applied to a wagon (mass 40 kg) at an angle of 30° to the horizontal. If the frictional force is 27.94 N, the magnitude of the resulting acceleration of the wagon is ___m/s2.

Expert's answer

Answer on Question#41295, Physics, Mechanics Question: A force of 90 N is applied to a wagon (mass 40 kg) at an angle of 30 to the horizontal. If the frictional force is 27.94 N, the magnitude of the resulting acceleration of the wagon is m/s2.

Solution. The projection of the applied force is

F=90Ncos30F=90N\cdot\cos 30{}^{\circ}

The resulting force is

FFfr=90Ncos3027.94=903/227.94=50NF-F_{fr}=90N\cdot\cos 30{}^{\circ}-27.94=90\cdot\sqrt{3}/2-27.94=50\,N

Then acceleration is

a=5040=1.2m/s2a=\frac{50}{40}=1.2\,m/s^{2}

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