Question

An engine provides 5.0 kN of force to keep a 1600-kg vehicle moving at a uniform speed. (Air resistance is negligible.) The coefficient of rolling friction between the tires and the road surface is ___.

Answer 1

Answer on Question #41291, Physics, Mechanics

Question:

An engine provides 5.0 kN of force to keep a 1600-kg vehicle moving at a uniform speed. (Air resistance is negligible.) The coefficient of rolling friction between the tires and the road surface is ___.

Answer:

Vehicle moving at a uniform speed therefore acceleration equals 0. Assuming Newton's first law of motion:

$$F = F_{fr}$$

where $F_{fr}$ is the friction force, $F$ is the force the engine.

Force of friction equals:

$$F_{fr} = \mu N = \mu m g$$

where $N$ is normal force, $mg$ is weight of the vehicle.

Coefficient of rolling friction equals:

$$\mu = \frac{F_{fr}}{mg} = \frac{F}{mg} = \frac{5000}{1600 \cdot 9.8} = 0.32$$

Answer: 0.32

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