Question

:
Two basketball players run into each other. Player 1, with a mass of 55.0 kg, experiences a –15.6 m/s2 acceleration. If player 2 has a mass of 48.5 kg, she experience and acceleration of ____ m/s2 immediately following the collision.

Answer 1

Answer on Question #41184, Physics, Mechanics

Question:

Two basketball players run into each other. Player 1, with a mass of 55.0 kg, experiences a –15.6 m/s² acceleration. If player 2 has a mass of 48.5 kg, she experience an acceleration of ____ m/s² immediately following the collision.

Answer:

From Newton’s third law of motion the size of the forces on the player 1 equals the size of the force on player 2 but they directed in opposite directions. Therefore acceleration of player 2 equals:

$$a _ {2} = - \frac {F _ {1}}{m _ {2}}$$

From Newton’s second law of motion force equals:

$$F _ {1} = m _ {1} a _ {1}$$

Therefore

$$a _ {2} = - \frac {m _ {1}}{m _ {2}} a _ {1} = \frac {5 5}{4 8 . 5} 1 5. 6 = 1 7. 7 \frac {m}{s ^ {2}}$$

Answer: 17.7 $\frac{m}{s^2}$

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