Question

a long wire hangs vertically with its upper end clamped. a torque of 6 Nm is applied to free end twist it through 60 dgree . the potential energy of twisted wire is??
ans in terms of pi..

Answer 1

Answer on Question #41161, Physics, Mechanics | Kinematics | Dynamics

A long wire hangs vertically with its upper end clamped. A torque of $6\mathrm{Nm}$ is applied to free end twist it through 60 degree. The potential energy of twisted wire is??

Answer in terms of pi.

Solution:

The elastic potential energy in a wire twisted by a torque $T$ at an angle $\theta$ is

$$U = \frac {T \theta}{2}$$ $$\theta = 6 0 {}^ {\circ} = \frac {\pi}{3}$$

Thus,

$$U = \frac {6 \cdot \pi}{2 \cdot 3} = \pi ]$$

Answer. $\pi$

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