Question #41093

The masses and radii of the earth and moon are M1, R1 and M2, R2 respectively. Their centres are at distance d apart. The minimum speed with which a particle of mass m should be projected from a point midway the two centres so as to escape to infinity is :-

Expert's answer

Answer on Question #41093, Physics, Mechanics | Kinematics | Dynamics

Question:

The masses and radii of the earth and moon are M1, R1 and M2, R2 respectively. Their centres are at distance dd apart. The minimum speed with which a particle of mass mm should be projected from a point midway the two centres so as to escape to infinity is :-

Answer:

The law of conservation of energy:


T+U=constT + U = \text{const}


where T=mv22T = \frac{mv^2}{2} is kinetic energy, mm - mass, vv - speed, U=GmMrU = -\frac{GmM}{r} is potential energy, rr is distance to the center of second body.

Therefore:


GM1md2GM2md2+mv22=0+0+0v2=4Gd(M1+M2)v=4Gd(M1+M2)\begin{array}{l} - \frac{G M_1 m}{\frac{d}{2}} - \frac{G M_2 m}{\frac{d}{2}} + \frac{m v^2}{2} = 0 + 0 + 0 \\ v^2 = \frac{4G}{d} (M_1 + M_2) \\ v = \sqrt{\frac{4G}{d} (M_1 + M_2)} \end{array}


Answer: v=4Gd(M1+M2)v = \sqrt{\frac{4G}{d} (M_1 + M_2)}

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