Question #41031

The Body Mass Index (BMI) is given by [BMI = mass / (height 2] where the mass is
measured in kg and height is measured in m. If a man of weight 800 N, and height 71 inches,
what is his BMI (in kg/m2)? Given that 1 m = 3.3 feet, and 1 foot =12 inches.

a) 11.3
b) 25.5
c) 28.2
d) 27.7
e) 23

Expert's answer

Answer on Question #41031, Physics, Mechanics

Question:

The Body Mass Index (BMI) is given by [BMI = mass / (height 2)] where the mass is measured in kg and height is measured in m. If a man of weight 800 N, and height 71 inches, what is his BMI (in kg/m²)? Given that 1 m = 3.3 feet, and 1 foot = 12 inches.

a) 11.3

b) 25.5

c) 28.2

d) 27.7

e) 23

Answer:

The Body Mass Index (BMI) is given by:


BMI=mh2BMI = \frac{m}{h^2}


where mm is mass measured in kg, hh is height is measured in m.

Weight of the man equals:


P=mgP = mg


therefore mass equals:


m=Pg=800N9.81m/s2=81.6kgm = \frac{P}{g} = \frac{800\,N}{9.81\,m/s^2} = 81.6\,kg


Height in meters equals:


h=71123.3=1.79mh = \frac{71}{12 \cdot 3.3} = 1.79\,m


Therefore:


BMI=81.51.792=25.5kgm2BMI = \frac{81.5}{1.79^2} = 25.5\,\frac{kg}{m^2}


Answer: b) 25.5


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