Question #41030

An object of mass 10 kg is pulled across a rough floor at a constant speed of 4 m/s using a force of
40 N, then the coefficient of kinetic friction is (ignoring air resistance):
a) 0.4 b) 4 c) Zero d) 0.25 e) 2.5

Expert's answer

Answer on Question #41030, Physics, Mechanics

An object of mass 10kg10\,\mathrm{kg} is pulled across a rough floor at a constant speed of 4m/s4\,\mathrm{m/s} using a force of 40N40\,\mathrm{N}, then the coefficient of kinetic friction is (ignoring air resistance):

a) 0.4 b) 4 c) Zero d) 0.25 e) 2.5

Solution:

The equation of motion is


FFfr=ma,F - F_{fr} = ma,


where force is F=40NF = 40\,\mathrm{N}, force of friction is Ffr=μNF_{fr} = \mu\mathrm{N} (N=mgN = mg, μ\mu is the coefficient of kinetic friction), the acceleration is a=0a = 0 (object is moved at a constant speed).

Thus,


Ffr=FF_{fr} = Fμmg=F\mu mg = Fμ=Fmg=40N10kg10m/s2=0.4\mu = \frac{F}{mg} = \frac{40\,\mathrm{N}}{10\,\mathrm{kg} \cdot 10\,\mathrm{m/s^2}} = 0.4


Answer. a) 0.4


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