Question

A typical laboratory centrifuge rotates at 4000 rev/min. What is the centripetal acceleration
at a point located 10 cm from the axis of rotation of the centrifuge?
a) 4.2×102 m/s2
b) 1.8×103 m/s2
c) 1.8×102 m/s2
d) 1.8×104 m/s2
e) 1.6×105 m/s2

Answer 1

Answer on Question#41026, Physics, Mechanics Question: A typical laboratory centrifuge rotates at 4000 rev/min. What is the centripetal acceleration at a point located 10 cm from the axis of rotation of the centrifuge? a) $4.2\cdot 10^{2}$ m/s2 b) $1.8\cdot 10^{3}m/s2$ c) $1.8\cdot 10^{2}$ m/s2 d) $1.8\cdot 10^{4}m/s2$ e) $1.6\cdot 10^{5}$ m/s2 Solution. Centripetal acceleration is

$a=\nu r$

where $\nu=4000rev/min=4000\cdot 2\pi/60\approx 419rad/s$ is angular speed and $r=0.1$ m is radius. Hence

$a=419\cdot 0.1\approx 4.2\cdot 10^{2}\,m/s^{2}$

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