Question #41019

A motorist travels 320 km at a speed of 80 km/h. It then traveled 320 km at a speed of 100
km/h along the same direction. What is the average speed of the motorist for the entire trip?
a) 84 km/h b) 90 km/h c) 89 km/h d) 91 km/h e) 95 km/h

Expert's answer

Answer on Question#41019 – Physics – Mechanics

A motorist travels 320 km at a speed of 80 km/h. It then traveled 320 km at a speed of 100 km/h along the same direction. What is the average speed of the motorist for the entire trip?

a) 84 km/h b) 90 km/h c) 89 km/h d) 91 km/h e) 95 km/h

Solution:

The average speed is the total distance divided by the total travel time.


Va=St(1)V_a = \frac{S}{t} \quad (1)


The total distance is


S=S1+S2(2)S = S_1 + S_2 \quad (2)


The total time is


t=t1+t2=S1V1+S2V2=S1V1+S2V2=S1V1+S2V2V1V2(3)t = t_1 + t_2 = \frac{S_1}{V_1} + \frac{S_2}{V_2} = \frac{S_1}{V_1} + \frac{S_2}{V_2} = \frac{S_1 V_1 + S_2 V_2}{V_1 V_2} \quad (3)


(3) and (2) in (1):


Va=S1+S2S1V1+S2V2V1V2=V1V2(S1+S2)S1V1+S2V2=80kmh100kmh(320km+320km)320km80kmh+320km100kmh=89kmhV_a = \frac{S_1 + S_2}{\frac{S_1 V_1 + S_2 V_2}{V_1 V_2}} = \frac{V_1 V_2 (S_1 + S_2)}{S_1 V_1 + S_2 V_2} = \frac{80 \frac{\text{km}}{\text{h}} \cdot 100 \frac{\text{km}}{\text{h}} (320 \text{km} + 320 \text{km})}{320 \text{km} \cdot 80 \frac{\text{km}}{\text{h}} + 320 \text{km} \cdot 100 \frac{\text{km}}{\text{h}}} = 89 \frac{\text{km}}{\text{h}}


Answer: c) 89 km/h

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