Question #41003

Ten seconds after an electric fan is turned on, it was fund to have an angular speed of
300 rev/min, Its average angular acceleration is:

1800 rev/sec2
3.14 rad/sec2
30 rad/sec2
30 rev/sec2
50 rev/min2

Expert's answer

Answer on Question #41003, Physics, Mechanics

Ten seconds after an electric fan is turned on, it was fund to have an angular speed of 300 rev/min, Its average angular acceleration is:

1800 rev/sec²

3.14 rad/sec²

30 rad/sec²

30 rev/sec²

50 rev/min²

Solution:

Rotation is described in terms of angular displacement , time , angular velocity, and angular acceleration . Angular velocity is the rate of change of angular displacement and angular acceleration is the rate of change of angular velocity.

Average angular acceleration:


α=ΔωΔt{\overline{\alpha}} = \frac{\Delta \omega}{\Delta t}


where Δω\Delta \omega is the rate of change of angular velocity in time Δt\Delta t.


Δω=ωfωi\Delta \omega = \omega_f - \omega_i


Given:


ωi=0\omega_i = 0ωf=300 rev/min=30060 rev/s=5 rev/s=52π rad/s\omega_f = 300 \text{ rev/min} = \frac{300}{60} \text{ rev/s} = 5 \text{ rev/s} = 5 \cdot 2\pi \text{ rad/s}Δt=10 s,\Delta t = 10 \text{ s},α=?{\overline{\alpha}} = ?α=ωfωiΔt=523.1410=3.14 rad/s2{\overline{\alpha}} = \frac{\omega_f - \omega_i}{\Delta t} = \frac{5 \cdot 2 \cdot 3.14}{10} = 3.14 \text{ rad/s}^2


Answer. 3.14 rad/sec²

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