Question #40982

Two waves 1 and 2 are present on a string:
(35mm) sin [(8.4m ) (15.7s ) ] 1 1
y1 x t
− − = −
(35mm) sin [(8.4m ) (15.7s ) ] 1 1
y2 x t
− − = +
(i) Write the expression for the resultant wave, y = y1 + y2 in the form of wave function
for a standing wave. (ii) Determine the x coordinates of the first two antinodes, starting at
the origin and progressing towards + x direction. (iii) Determine the x coordinate of the
node that is between the antinodes of part (ii).

Expert's answer

Answer on Question #40982, Physics, Mechanics | Kinematics | Dynamics

Two waves 1 and 2 are present on a string:


y1=(35 mm)sin[(8.4m1)x(15.7s1)t]y1 = (35 \text{ mm}) \sin[(8.4m^{\wedge} - 1)x - (15.7s^{\wedge} - 1)t]y2=(35 mm)sin[(8.4m1)x+(15.7s1)t]y2 = (35 \text{ mm}) \sin[(8.4m^{\wedge} - 1)x + (15.7s^{\wedge} - 1)t]


(i) Write the expression for the resultant wave, y=y1+y2y = y1 + y2 in the form of wave function for a standing wave.

(ii) Determine the xx coordinates of the first two antinodes, starting at the origin and progressing towards ++ xx direction.

(iii) Determine the xx coordinate of the node that is between the antinodes of part (ii).

Solution

(i) Two waves 1 and 2 are present on a string:


y1=35sin(8.4x15.7t),y_1 = 35 \sin(8.4x - 15.7t),y2=35sin(8.4x+15.7t).y_2 = 35 \sin(8.4x + 15.7t).


The sum of these two waves is:


y=y1+y2=35sin(8.4x15.7t)+35sin(8.4x+15.7t).y = y_1 + y_2 = 35 \sin(8.4x - 15.7t) + 35 \sin(8.4x + 15.7t).


We can use formulae for the sum of sinuses:


sina+sinb=2sina+b2cosab2.\sin a + \sin b = 2 \sin \frac{a + b}{2} \cos \frac{a - b}{2}.


So


y=y1+y2=70sin(8.4x)cos(15.7t).y = y_1 + y_2 = 70 \sin(8.4x) \cos(15.7t).


(ii) The positions of the antinodes are given by


x=λ4,3λ4,5λ4,,(2n1)λ4,n=1,2,3x = \frac{\lambda}{4}, \frac{3\lambda}{4}, \frac{5\lambda}{4}, \dots, \frac{(2n - 1)\lambda}{4}, n = 1,2,3 \dots


In our case k=2πλ=8.4radmk = \frac{2\pi}{\lambda} = 8.4 \frac{rad}{m} and the wavelength is λ=2π8.4=0.748m\lambda = \frac{2\pi}{8.4} = 0.748 \, m.

The xx coordinates of the first two antinodes are


x1=λ4=0.187m,x_1 = \frac{\lambda}{4} = 0.187 \, m,x2=3λ4=0.561m.x_2 = \frac{3\lambda}{4} = 0.561 \, m.


(iii) The node is located at


x=λ2=0.374m.x = \frac{\lambda}{2} = 0.374 \, m.


Answer: (i) 70sin(8.4x)cos(15.7t)70 \sin(8.4x) \cos(15.7t); (ii) 0.187m0.187 \, m, 0.561m0.561 \, m; (iii) 0.374m0.374 \, m.

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