A BLOCK SLIDES DOWN AN INCLINED PLANE OF SLOPE ANGLE THETA WITH A CONSTANT VELOCITY. IT IS THEN PROJECTED UP THE PLANE WITH AN INITIAL VELOCITY U. DISTANCE UPTO WHICH IT WILL RISE BEFORE COMING TO REST IS ?
1. We consider the downward motion with a constant velocity. It means
that there is no acceleration and gravity is balanced by the friction
force (see Eq. 1). It allows to calculate the coefficient of friction.
2. When one projects a block up the plane, the friction force changes
its direction to opposite (downward). The balance of forces breaks and
a block decelerates. Here we calculate the work done by friction: it
equals initial kinetic energy mu^2/2 (see Eq. 5).
Sanjeev
07.04.14, 00:23
not understood....plz explain
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1. We consider the downward motion with a constant velocity. It means that there is no acceleration and gravity is balanced by the friction force (see Eq. 1). It allows to calculate the coefficient of friction. 2. When one projects a block up the plane, the friction force changes its direction to opposite (downward). The balance of forces breaks and a block decelerates. Here we calculate the work done by friction: it equals initial kinetic energy mu^2/2 (see Eq. 5).
not understood....plz explain
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