Question

A cyclist and cycle have a combined mass of 78 kg as they accelerate along a race track at 2.5 m/s2. Calculate the fore exerted as they accelerate. ( F= 195 N ) I solved this , but I do not know other one, which is :
A lift of mass 400 kg is accelerated upwards at 2 m/s2. calculate the force in the rope pulling.

Please help me. Many thanks

Answer 1

Answer on Question #40797 – Physics – Mechanics

A cyclist and cycle have a combined mass of 78 kg as they accelerate along a race track at 2.5 m/s². Calculate the fore exerted as they accelerate. ( F = 195 N ) I solved this, but I do not know other one, which is:

A lift of mass 400 kg is accelerated upwards at 2 m/s². Calculate the force in the rope pulling.

Solution:

Task 1

m = 78 kg – mass of the cyclist and cycle;

a = 2.5 m/s² – acceleration of the cycle;

Newton’s second law for the cycle along the X-axis:

x: F = ma = 78kg · 2.5 m/s² = 195 N

Answer: fore exerted as cyclist and cycle accelerate is equal to 195 N.

Task 2

m = 400 kg – mass of the lift;

g = 9.8 m/s² – acceleration due to gravity;

a = 2 m/s² – acceleration of the lift;

Newton’s second law for the lift along the Y-axis:

F – mg = ma

F = ma + ma = m(a + g) = 400 kg (9.8 m/s² + 2 m/s²) = 4720 N

Answer: the force in the rope pulling is equal to 4720 N.

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