Question #40679

A bacteria of mass 2 × 10−24 kg is rotated in a centrifuge at an angular speed of 4p × 103 rad s−1.
It is situated at a distance of 5 cm from the axis of rotation. Calculate the effective value of g
relative to the rotating frame of reference and the net centrifugal force on the bacteria.

Expert's answer

Answer on Question #40679, Physics, Mechanics | Kinematics | Dynamics

Question:

A bacteria of mass 2×1024kg2 \times 10^{-24} \, \mathrm{kg} is rotated in a centrifuge at an angular speed of 4p×1034p \times 103 rad s1^{-1}. It is situated at a distance of 5cm5 \, \mathrm{cm} from the axis of rotation. Calculate the effective value of gg relative to the rotating frame of reference and the net centrifugal force on the bacteria.

Answer:

Centrifugal acceleration (effective value of gg) equals:


a=ω2r=7.9106ms2a = \omega^{2} r = 7.9 \cdot 10^{6} \frac{m}{s^{2}}


where ω\omega is angular speed, rr is distance from the axis of rotation.

Net centrifugal force on the bacteria equals:


F=ma=1.61017NF = m a = 1.6 \cdot 10^{-17} \, N


where mm is mass, aa is acceleration

Answer: a=7.9106ms2,F=1.61017Na = 7.9 \cdot 10^{6} \frac{m}{s^{2}}, F = 1.6 \cdot 10^{-17} \, N

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