Question

The distance between 2 consecutive crests of waves of water colliding with a boat tied to an anchor is 100 m.If velocity of wave is 20 m/s,then after how much time would the wave collide with the boat? What would be the frequency of wave colliding with the boat?

Answer 1

Answer on Question#40534, Physics, Mechanics

Question:

The distance between 2 consecutive crests of waves of water colliding with a boat tied to an anchor is $100\,\mathrm{m}$. If velocity of wave is $20\,\mathrm{m/s}$, then after how much time would the wave collide with the boat? What would be the frequency of wave colliding with the boat?

Answer:

The frequency $f$ of wave is equal to the phase velocity $v$ of the wave divided by the wavelength $\lambda$ of the wave:

$$f = \frac{v}{\lambda} = \frac{20\,\frac{\mathrm{m}}{\mathrm{s}}}{100\,\mathrm{m}} = 0.2\,\mathrm{Hz}$$

Therefore, the wave will collide with the boat after:

$$T = \frac{1}{f} = \frac{1}{0.2} = 5\,\mathrm{s}$$

Answer: $T = 5\,\mathrm{s}, f = 0.2\,\mathrm{Hz}$