Question

the particle is projected with v=6i+3xj. find eqn of path followed
a.y=x2(2-square)
b.y=2x2
c.y=1/2x2

Answer 1

Answer on Question#40419 – Physics - Mechanics | Kinamatics | Dynamics

the particle is projected with $v = 6i + 3xj$. find eqn of path followed

a.y = x²(2-square)

b.y = 2x²

c.y = 1/2x²

Solution:

Velosity of the particle:

$$\vec{v} = \vec{v_x} + \vec{v_y} = v_x \vec{i} + v_y \vec{j} = 6i + 3xj$$ $$v_x = 6 \Rightarrow x = 6t$$ $$v_y = 3x = 3 \cdot 6t = 18t \Rightarrow y = 18t \cdot t = 18t^2$$ $$y = \frac{x^2}{2} \left( \text{because } \frac{(6t)^2}{2} = \frac{36t^2}{2} = 18t^2 \right)$$

Answer: a. $y = x^2$