Question

If a force of 80N extends a spring of natural length 8m by 0.4m what will be the length of the spring when the applied force is 100N

Answer 1

Answer on 40290, Physics, Mechanics | Kinematics | Dynamics

Question: If a force of 80N ex- tends a spring of natural length 8m by 0.4m

what will be the length of the spring when the applied force is 100N.

Solution. First, let us determine the spring constant

$k=\frac{F_{1}}{\Delta x_{1}}$

where $F_{1}=80N$ and $\Delta x_{1}$. Then, the spring will extend under the force of 100N on

$\Delta x_{2}=\frac{F_{2}}{k}$

Hence, length will be

$L+\Delta x_{2}=L+\frac{F_{2}x_{1}}{F_{1}}=8+\frac{100\cdot 0.4}{80}=8.5\,m$