Question

A wire of cross-sectional area of
6×10−5m2
and length 50cm stretches by 0.2mm under a load of 3000N. Calculate the Young’s modulus for the wire

8×1010Nm−2

1:25×1011Nm−2

2:5×1011Nm−2

5×1011Nm−2

Answer 1

Answer on 40289, Physics, Mechanics | Kinematics | Dynamics

Question: A wire of cross-sectional area of 6$\cdot 10^{-5}$ m2 and length 50cm stretches by 0.2mm under a load of 3000N. Calculate the Youngs modulus for the wire Solution. Young’s modulus is:

$E=\frac{F/S}{\Delta l/l}=\frac{3000/(6\cdot 10^{-5})}{0.2\cdot 10^{-3}/50}=12.5\cdot 10^{11}Pa$