Question

a 5kg block is pulled acroos a tableby a horizontalforce 40N with frictional force of 8N opposing the motion.calculate the acceleration of thee object..."

Answer 1

Answer on Question#39776 – Physics – Other

a 5kg block is pulled across a table by a horizontal force 40N with frictional force of 8N opposing the motion. Calculate the acceleration of the object...

Solution:

$$\begin{array}{l} F_1 = 40N - \text{horizontal force}; \\ F_{\text{frict}} = 8N - \text{frictional force}; \\ m = 5kg - \text{mass of the block}; \end{array}$$

Newton's second law for the block (initial position):

$$\begin{array}{l} x: F_1 - F_{\text{frict}} = ma \\ a = \frac{F_1 - F_{\text{frict}}}{m} = \frac{40N - 8N}{5kg} = 6.4 \frac{m}{s^2} \end{array}$$

Answer: acceleration of the object is equal to $6.4 \frac{m}{s^2}$.