Answer on Question #39603, Physics, Mechanics | Kinematics | Dynamics
Question:
what is the cross product A > < B A >< B A >< B under mirror reflection
Answer:
If a point of an object has coordinates ( x , y , z ) (x, y, z) ( x , y , z ) then the image of this point (as reflected by a mirror in the y y y , z z z plane) has coordinates ( − x , y , z ) (-x, y, z) ( − x , y , z ) .
Suppose A ⃗ × B ⃗ = C ⃗ \vec{A} \times \vec{B} = \vec{C} A × B = C
Therefore, cross product transforms:
A ′ → × B ′ → = ∣ i ⃗ j ⃗ k ⃗ − A x A y A z − B x B y B z ∣ = i ⃗ C x − j ⃗ C y − k ⃗ C z = ( C x − C y − C z ) \overrightarrow{A'} \times \overrightarrow{B'} = \left| \begin{array}{ccc} \vec{i} & \vec{j} & \vec{k} \\ -A_x & A_y & A_z \\ -B_x & B_y & B_z \end{array} \right| = \vec{i} C_x - \vec{j} C_y - \vec{k} C_z = \begin{pmatrix} C_x \\ -C_y \\ -C_z \end{pmatrix} A ′ × B ′ = ∣ ∣ i − A x − B x j A y B y k A z B z ∣ ∣ = i C x − j C y − k C z = ⎝ ⎛ C x − C y − C z ⎠ ⎞
Answer: A ′ → × B ′ → = ( ( A ⃗ × B ⃗ ) x − ( A ⃗ × B ⃗ ) y − ( A ⃗ × B ⃗ ) z ) \overrightarrow{A'} \times \overrightarrow{B'} = \begin{pmatrix} (\vec{A} \times \vec{B})_x \\ -(\vec{A} \times \vec{B})_y \\ -(\vec{A} \times \vec{B})_z \end{pmatrix} A ′ × B ′ = ⎝ ⎛ ( A × B ) x − ( A × B ) y − ( A × B ) z ⎠ ⎞